Asked by James

Calculate Delta H for the reaction CH4(g)+NH3(g)-->HCN(g)+3H2(g) given,

N2(g)+3H2(g)->2NH3(g) DeltaH=-91.8kj
C(s)+2H2(g)->CH3(g) DeltaH=-74.9kj
h2(g)+2C(s)+N2(g)->2HCN(g) DeltaH=270.3kj

Answers

Answered by DrBob222
Add the reverse of eqn 1 to 2x the reverse of equation 2 to eqn 3, then take 1/2 of the sum. Post your work if you gets stuck.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions