Asked by George
If it takes three "breaths" to blow up a balloon to 1.2 , and each breath supplies the balloon with 0.060 moles of exhaled air, how many moles of air are in a 3.0 balloon.
Express your answer in moles using two significant figures
Would the answer be 0.38 mol?
Express your answer in moles using two significant figures
Would the answer be 0.38 mol?
Answers
Answered by
GK
Is it 1.2 L and 3.0 L ? If so,
1.2 L / 3 breaths = 0.4 L / breath
(3.00 L) / (0.4 L / breath) = 7.5 breaths
(7.5 breaths)(0.060 mol/breath) = 0.45moles
1.2 L / 3 breaths = 0.4 L / breath
(3.00 L) / (0.4 L / breath) = 7.5 breaths
(7.5 breaths)(0.060 mol/breath) = 0.45moles
Answered by
Thato Mokwena
we have 1.2 L and 3.0 L
therefore
1.2 L / 3 breaths = 0.4 L / breath
(3.00 L) / (0.4 L / breath) = 7.5 breaths
(7.5 breaths)(0.060 mol/breath) = 0.45moles
therefore
1.2 L / 3 breaths = 0.4 L / breath
(3.00 L) / (0.4 L / breath) = 7.5 breaths
(7.5 breaths)(0.060 mol/breath) = 0.45moles
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