Asked by Laly
The equation, in general form, of the line that passes through the point (−5,6) and is parallel to the line 3x−3y+2=0 is Ax+By+C=0, where A=?, B=? and C=11.
Answers
Answered by
Steve
well, just plug in the point:
3(-5)-3(6)+2 = -15-18+2 = -31
so,
3x-3y+2 = -31
3x-3y+33 = 0
x-y+11 = 0
3(-5)-3(6)+2 = -15-18+2 = -31
so,
3x-3y+2 = -31
3x-3y+33 = 0
x-y+11 = 0
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