Asked by Allison
Given: B is the midpoint of line AC. D is the midpoint of line CE. Ab=De
Prove AE=4AB
Prove AE=4AB
Answers
Answered by
Steve
assuming that ABCDE are points in that order, draw the line and mark 'em off.
AB=BC
CD=DE
AE = AB+BC+CD+DE = AB+AB+DE+DE = AB+AB+AB+AB = 4AB
AB=BC
CD=DE
AE = AB+BC+CD+DE = AB+AB+DE+DE = AB+AB+AB+AB = 4AB
Answered by
Allison
I have AB=Bc Theorem of Midpoint
CD=DE Theorem of midpoint
BC=CD Definition of Congruency
AB=CD Def. Of Con
AB+BC=AD Seg. addition post.
CD+DE=CE Seg. Addition Postu.
ABC+CDE=AE Seg, Addition postulate
Cis midpoint of AE midpoint Theorem.
My teacher wants 17 steps!
CD=DE Theorem of midpoint
BC=CD Definition of Congruency
AB=CD Def. Of Con
AB+BC=AD Seg. addition post.
CD+DE=CE Seg. Addition Postu.
ABC+CDE=AE Seg, Addition postulate
Cis midpoint of AE midpoint Theorem.
My teacher wants 17 steps!