Asked by liko
how many whole numbers from 100 to 1000 contain the digit 6 exactly twice?
Sorry about the other post, it's wrong.
Sorry about the other post, it's wrong.
Answers
Answered by
Reiny
number of cases:
(X is any digit except 6)
6XX = 9X9 = 81
X6X = 8x9 = 72 , can't have 0 at the front
XX6 = 8x9 = 72
66X = 9
6X6 = 9
X66 = 8
Number of cases = add them up
(X is any digit except 6)
6XX = 9X9 = 81
X6X = 8x9 = 72 , can't have 0 at the front
XX6 = 8x9 = 72
66X = 9
6X6 = 9
X66 = 8
Number of cases = add them up
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