Asked by Ryan
find the solutions to the equation;
x^(2/5)-8x(1/5)+16=0
x^(2/5)-8x(1/5)+16=0
Answers
Answered by
Steve
let u = x^(1/5)
The equation then becomes
u^2-8u+16 = 0
(u-4)^2 = 0
u = 4
so, x^(1/5) = 4
x = 4^5 = 1024
The equation then becomes
u^2-8u+16 = 0
(u-4)^2 = 0
u = 4
so, x^(1/5) = 4
x = 4^5 = 1024
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