Asked by b.s. chandrshekar
Ammonia may be oxidised to nitrogen monoxide
in the presence of catalyst according to the equation 4 NH3 + 5 O2 gives 4 NO and 6 H2O. If 27 litres of reactants are consumed , what volume of nitrogen monoxide is produced at the same temperature and pressure.
in the presence of catalyst according to the equation 4 NH3 + 5 O2 gives 4 NO and 6 H2O. If 27 litres of reactants are consumed , what volume of nitrogen monoxide is produced at the same temperature and pressure.
Answers
Answered by
bobpursley
if you started with 27 liters, you will get 10/9 x 27 liters of products.
of that, NO will be .4*10/9*27 liters
and steam will be .6*10/9*27 liters.
of that, NO will be .4*10/9*27 liters
and steam will be .6*10/9*27 liters.
Answered by
disha soni
if you started with 27 liters, you will get 10/9 x 27 liters of products.
of that, NO will be .4*10/9*27 liters
and steam will be .6*10/9*27 liters.
of that, NO will be .4*10/9*27 liters
and steam will be .6*10/9*27 liters.
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