Asked by epis
how to prepare 1 L of 2.5M nitric acid from 69% of concentrated nitric acid?
Answers
Answered by
DrBob222
Do you know the density.
1000 x density(g/mL) x 0.69 x (1/63) = ?M = approx 14M but you need that more accurate than that.
Then mL1 x M1 = mL2 x M2
1000 x 2.5M = mL2 x approx 14
Solve for mL2, add that amount to a 1L volumetric flask, make to the mark, stopper, share thoroughly.
1000 x density(g/mL) x 0.69 x (1/63) = ?M = approx 14M but you need that more accurate than that.
Then mL1 x M1 = mL2 x M2
1000 x 2.5M = mL2 x approx 14
Solve for mL2, add that amount to a 1L volumetric flask, make to the mark, stopper, share thoroughly.
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