k = 0.693/t1/2
Then
ln(No/N) = kt
No = 0.766
N = solve for this
k from above
t = 8.40 hr
The strontium-87 isotopes stores in the body and decays by the process shown below. The half-life is 2.80hr. Suppose that 0.766 millicuries got into the body. How many mc will remain after 8.40 hr?
2 answers
2.30