Asked by Tracy
Find the missing coordinate of p, using the fact that p lies on the unit circle in the given quadrant.
P( ), -3/7
P( ), -3/7
Answers
Answered by
Reiny
do you mean P( ...., -3/7) ?
x^2 + (-3/7)^2 = 1^2
x^2 = 1 - 9/49 = 40/49
x = ±√40/7 = ± 2√10/7
we see that the y is negative, so the point could be in III or IV, thus the ±
x^2 + (-3/7)^2 = 1^2
x^2 = 1 - 9/49 = 40/49
x = ±√40/7 = ± 2√10/7
we see that the y is negative, so the point could be in III or IV, thus the ±
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