Question
A car is braked so that it slows down with uniform retardation from 15 m/s to 7 m/s while it travels a distance of 88 m. If the car continues to slow down at the same rate, after what further distance will it be brought to rest?
Answers
Henry
d1 = 88 m.
V^2 = Vo^2 + 2a*d1.
a = (V^2-Vo^2)/2d1=(7^2-15^2)/176 = -1.0 m/s^2.
d2 = (V^2-Vo^2)/2a=(0-15^2)/-1.0 = 225 m
d = d2-d1 = 225 - 88 = 137 m.
V^2 = Vo^2 + 2a*d1.
a = (V^2-Vo^2)/2d1=(7^2-15^2)/176 = -1.0 m/s^2.
d2 = (V^2-Vo^2)/2a=(0-15^2)/-1.0 = 225 m
d = d2-d1 = 225 - 88 = 137 m.
rk
in my book answer is 24.5
Muhammad ashemi
He travel at this speed far 4second. Brake are then apply and the body come to rest with uniform retardation in a further second graph of speed against time use the fine car acceleration
aman
its wrong