Asked by anonymous
how long will it take for a car to accelerate to come to a stop if it is traveling at 20 m/s and the car has a maximum deceleration of 6 m/s squared?
So far I think im supposed to do
6-20/26
So far I think im supposed to do
6-20/26
Answers
Answered by
Steve
Think of the units:
(20 m/s) / (6 m/s^2) = 3.33 s
Think of it like this. Every second the speed decreases by 6 m/s. So, it takes 3.33 seconds to lose all 20 m/s.
Or, how about this:
a = ∆v/∆t
so, ∆t = ∆v/a = (0-20)/-6 = = 3.33
(20 m/s) / (6 m/s^2) = 3.33 s
Think of it like this. Every second the speed decreases by 6 m/s. So, it takes 3.33 seconds to lose all 20 m/s.
Or, how about this:
a = ∆v/∆t
so, ∆t = ∆v/a = (0-20)/-6 = = 3.33
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