Asked by Nick
A 11.0-µF capacitor and a 50.0-µF capacitor are charged by being connected across separate 55.0-V batteries.
(a) Determine the resulting charge on each capacitor.
(b) The capacitors are then disconnected from their batteries and connected to each other, with each negative plate connected to the other positive plate. What is the final charge of each capacitor?
(c) What is the final potential difference across the 50.0-µF capacitor?
Are these connected in series or parallel?
(a) Determine the resulting charge on each capacitor.
(b) The capacitors are then disconnected from their batteries and connected to each other, with each negative plate connected to the other positive plate. What is the final charge of each capacitor?
(c) What is the final potential difference across the 50.0-µF capacitor?
Are these connected in series or parallel?
Answers
Answered by
Henry
a. Q1 = C*V = 11 * 55 = Micro Coulombs.
Q2 = 50 * 55 = Micro Coulombs.
b. The capacitors will discharge:
Q = C*V = 61 * 0 = 0.
c. 0 volts.
Q2 = 50 * 55 = Micro Coulombs.
b. The capacitors will discharge:
Q = C*V = 61 * 0 = 0.
c. 0 volts.
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