Asked by Lucy
Consider a class with 10 sophomores, 8 juniors, and 6 seniors. Two students are selected at random.
1) What is the probability of selecting 1 junior and 1 senior.
2) Find the odds of selecting two students who are not seniors.
How do I set these up to solve??
Any help is greatly appreciated!!
1) What is the probability of selecting 1 junior and 1 senior.
2) Find the odds of selecting two students who are not seniors.
How do I set these up to solve??
Any help is greatly appreciated!!
Answers
Answered by
bobpursley
the total students are 24.
Probability of 1junior and 1 senior are..
Pr=(8/24)(6/23)
The second:
Pr=(18/24)(17/23)
Notice in each, the numerator is the number of possible ways to be successful,the denominator is the number of ways it can go.
Probability of 1junior and 1 senior are..
Pr=(8/24)(6/23)
The second:
Pr=(18/24)(17/23)
Notice in each, the numerator is the number of possible ways to be successful,the denominator is the number of ways it can go.
Answered by
Isabella
For number one, there is a total of 24 students when you add 10+8+6. Then you want to find 1 junior and 1 senior which added up becomes 2. soo....
2/24 = 1/12 reduced! :)
2/24 = 1/12 reduced! :)
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