Asked by GraceW1
It takes a freely falling object 1.80 s to travel the last 32.00 m before it hits the ground. From how high of the ground did it fall? Assume it starts from rest.
Answers
Answered by
Henry
V1*t + 0.5g*t^2 = 32.
V1*1.8 + 4.9*1.8^2 = 32.
1.8V1 = 32 - 15.88 = 16.12.
V1 = 9.0 m/s. = Velocity at the beginning of the last 32 m.
h = (V1^2-Vo^2)/2g + 32 =
(9^2-0)/19.6 + 32 = 36.13 m.
V1*1.8 + 4.9*1.8^2 = 32.
1.8V1 = 32 - 15.88 = 16.12.
V1 = 9.0 m/s. = Velocity at the beginning of the last 32 m.
h = (V1^2-Vo^2)/2g + 32 =
(9^2-0)/19.6 + 32 = 36.13 m.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.