V = g*t
V = 20*1 = 20 m/s.
V = 20*2 = 40 m/s.
V = 20*3 = 60 m/s.
Increase = 20 m/s with each second.
If a freely falling rock were equipped with a speedometer, by how much would its speed readings increase with each second IF it were on a planet where g = 20 m/s2?
Show all work leading to your answer.
g=20 m/s^2
20 m/s
V=gt
S=g( T ^2) / 2
Is this right ?
1 answer