Asked by paresh
A resultant force of 20 N gives a body of mass m an acceleration of 8 m/s^2 and a body of mass m' acceleration of 24 m/s^2. What acceleration will this force cause the two masses to acquire if fastened together.
Answers
Answered by
Ruel VT
F = 20N
A1 = 8 m/s^2
A2 = 24 m/s^2
F = ma
M1 = F/A1
M1 = 20N/8 m/s^2
M1 = 2.25 kg
F = ma
M2 = F/A2
M2 = 20N/ 24 m/s^2
M2 = 0.83 kg
M1 + M2 = 3.33 kg
a = F/M
a = 20N / 3.33 kg
a = 6.01 m/s^2
A1 = 8 m/s^2
A2 = 24 m/s^2
F = ma
M1 = F/A1
M1 = 20N/8 m/s^2
M1 = 2.25 kg
F = ma
M2 = F/A2
M2 = 20N/ 24 m/s^2
M2 = 0.83 kg
M1 + M2 = 3.33 kg
a = F/M
a = 20N / 3.33 kg
a = 6.01 m/s^2
Answered by
Ruel VT
F = 20N
A1 = 8 m/s^2
A2 = 24 m/s^2
F = ma
M1 = F/A1
M1 = 20N/8 m/s^2
M1 = 2.50 kg
F = ma
M2 = F/A2
M2 = 20N/ 24 m/s^2
M2 = 0.83 kg
M1 + M2 = 3.33 kg
a = F/M
a = 20N / 3.33 kg
a = 6.01 m/s^2
A1 = 8 m/s^2
A2 = 24 m/s^2
F = ma
M1 = F/A1
M1 = 20N/8 m/s^2
M1 = 2.50 kg
F = ma
M2 = F/A2
M2 = 20N/ 24 m/s^2
M2 = 0.83 kg
M1 + M2 = 3.33 kg
a = F/M
a = 20N / 3.33 kg
a = 6.01 m/s^2
Answered by
DAVID
Correct 👍👍
Answered by
Karan Jack
F=20N
a1=8m/s^2
a2=24m/s^2
Let mass in first case be m1,
and mass in second case be m2.
1st case,
F=m1a2
m1=F/a1
=20/8
=5/2
2nd case,
F=m2a2
m2=F/a2
=20/24
=5/6
Total mass=m1+m2
=5/2 + 5/6
=10/3
a=F/total mass
=20/10/3
=20×3/10
=60/10
=6m/s^2.
a1=8m/s^2
a2=24m/s^2
Let mass in first case be m1,
and mass in second case be m2.
1st case,
F=m1a2
m1=F/a1
=20/8
=5/2
2nd case,
F=m2a2
m2=F/a2
=20/24
=5/6
Total mass=m1+m2
=5/2 + 5/6
=10/3
a=F/total mass
=20/10/3
=20×3/10
=60/10
=6m/s^2.