Asked by Tega
Find the resultant of the forces 10N and 15N with an angle of 120 between them.
Answers
Answered by
Damon
say 15 N along x axis
and 10 N 60 deg above -x axis
x force = 15 - 10 cos 60 = 10
y force = 10 sin 60 = 8.66
magnitude = sqrt(100+8.66^2)
tan angle above +x axis = .866
and 10 N 60 deg above -x axis
x force = 15 - 10 cos 60 = 10
y force = 10 sin 60 = 8.66
magnitude = sqrt(100+8.66^2)
tan angle above +x axis = .866
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