Asked by Tiffany
A pure silver ring contains 2.60X10^22 silver atoms. How many moles of silver atoms it contain?
Answers
Answered by
DrBob222
1 mole is anything is 6.022E23 so
2.60E22 atoms Ag x (1 mol Ag/6.022E23) =?
2.60E22 atoms Ag x (1 mol Ag/6.022E23) =?
Answered by
Tiffany
I did the calculation and I got 4.32 X10^44. Is that correct?
Answered by
DrBob222
No.
2.60E22/6.022E23 = 0.0432
Did you punch in those numbers on your calculator? The digits are right; the exponent is not. 10^22/10^23 = 10^-1 or 0.1
2.60E22/6.022E23 = 0.0432
Did you punch in those numbers on your calculator? The digits are right; the exponent is not. 10^22/10^23 = 10^-1 or 0.1
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