Asked by Arun
The volume of 0.025M Ca(OH)2 solution which can neutralise 100ml of0.0001M H3PO4
Answers
Answered by
DrBob222
3Ca(OH)2 + 2H3PO4 ==> Ca3(PO4)2 + 6H2O
mols H3PO4 = M x L = ?
Using the coefficients in the balanced equation, convert mols H3PO4 to mols Ca(OH)2.
Now M Ca(OH)2 = mols Ca(OH)2/L Ca(OH)2. You know M and mols, solve for L.
mols H3PO4 = M x L = ?
Using the coefficients in the balanced equation, convert mols H3PO4 to mols Ca(OH)2.
Now M Ca(OH)2 = mols Ca(OH)2/L Ca(OH)2. You know M and mols, solve for L.