Asked by donia

A bicycl rider starts from rest and moves with uniform acceration of 1.5m\s^2 it is velocity reachs 7.5m\s of a distance .......






















Answers

Answered by donia
d=v*t
d=7.5*5=35.5m
Answered by Henry
V = a*t = 7.5 m/s.
1.5*t = 7.5.
t = 5 s.

d = 0.5a*t^2 = 0.5*1.5*5^2 = 18.75 m.
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