Asked by roseann
wright the slope-intercept form of the equation of the line described though:(-2,5), parallel to y=-9/2x+3
Answers
Answered by
Ms. Sue
And another misspelled post from the person in Texas who seems to have an identity problem.
Answered by
paul
Slope of parallel lines are the same. m = -9/2 here so the new line will have a slope of m= -9/2 as well.
Through the points (-2,5)
y-y1=m(x-x1)
y-5=(-9/2)(x--2)
y-5=(-9/2)(x+2)
y-5=(-9/2)x+(-9)
y=(-9/2)x-4.
Through the points (-2,5)
y-y1=m(x-x1)
y-5=(-9/2)(x--2)
y-5=(-9/2)(x+2)
y-5=(-9/2)x+(-9)
y=(-9/2)x-4.
Answered by
Steve
Or, using
y(x) = -9/2 x + 3,
y(-2) = 9+3 = 12
You want y(-2) = 5, so you have to subtract 7 from the given value, leaving you with
y = -9/2 x - 4
y(x) = -9/2 x + 3,
y(-2) = 9+3 = 12
You want y(-2) = 5, so you have to subtract 7 from the given value, leaving you with
y = -9/2 x - 4
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