wright the slope-intercept form of the equation of the line described though:(-2,5), parallel to y=-9/2x+3

3 answers

And another misspelled post from the person in Texas who seems to have an identity problem.
Slope of parallel lines are the same. m = -9/2 here so the new line will have a slope of m= -9/2 as well.

Through the points (-2,5)

y-y1=m(x-x1)
y-5=(-9/2)(x--2)
y-5=(-9/2)(x+2)
y-5=(-9/2)x+(-9)

y=(-9/2)x-4.
Or, using
y(x) = -9/2 x + 3,
y(-2) = 9+3 = 12

You want y(-2) = 5, so you have to subtract 7 from the given value, leaving you with

y = -9/2 x - 4