wright the slope-intercept form of the equation of the line described though:(-2,5), parallel to y=-9/2x+3
3 answers
And another misspelled post from the person in Texas who seems to have an identity problem.
Slope of parallel lines are the same. m = -9/2 here so the new line will have a slope of m= -9/2 as well.
Through the points (-2,5)
y-y1=m(x-x1)
y-5=(-9/2)(x--2)
y-5=(-9/2)(x+2)
y-5=(-9/2)x+(-9)
y=(-9/2)x-4.
Through the points (-2,5)
y-y1=m(x-x1)
y-5=(-9/2)(x--2)
y-5=(-9/2)(x+2)
y-5=(-9/2)x+(-9)
y=(-9/2)x-4.
Or, using
y(x) = -9/2 x + 3,
y(-2) = 9+3 = 12
You want y(-2) = 5, so you have to subtract 7 from the given value, leaving you with
y = -9/2 x - 4
y(x) = -9/2 x + 3,
y(-2) = 9+3 = 12
You want y(-2) = 5, so you have to subtract 7 from the given value, leaving you with
y = -9/2 x - 4