you can always check your answers at wolframalpha.com
As you can see, you're way off.
If h = 3e^u where u is a function of x, then
h' = 3e^u du/dx
= 3e^(sin(x+2)) * cos(x+2)
http://www.wolframalpha.com/input/?i=derivative+3e^%28sin%28x%2B2%29%29
Hello,
Could somebody kindly check my answer for the following question?
Find the derivative of the following function:
h(x)=3e^(sin(x+2))
h'(x)=3'(e^(sin(x+2))+3(e^(sin(x+2))'
h'(x)=0(e^(sin(x+2))+3(e^(sin(x+2))(cos(1))
h'(x)=3cos1(e^(sin(x+2))
I would greatly appreciate your help.
Constantine
2 answers
Thank you Steve.