Question
A ship travels 100 km due north on the first day of a voyage, 60 km north-east on the second day, and 120 km due east on the third day. Find the resultant displacement.
Answers
Damon
North:
100 + 60(.5 sqrt 2 ) = 142
East:
60(.5 sqrt 2) + 120 = 162
Tan angle east of north (compass course made good) = 162/142 = 1.14
so
angle east of north = 48.7 degrees
distance from start = sqrt(162^2+142^2)
100 + 60(.5 sqrt 2 ) = 142
East:
60(.5 sqrt 2) + 120 = 162
Tan angle east of north (compass course made good) = 162/142 = 1.14
so
angle east of north = 48.7 degrees
distance from start = sqrt(162^2+142^2)