A ship travels due north for 25 miles then changes course to a bearing of 300°. It travels on this path for 29 miles. How far is the ship from where it started?

Answer 1

Sum the east (x-) and north (y-) components.

x=∑D cos(θ)
=25*cos(90°)+29 cos(90-300°)
=0+29cos(-210)
=-(29/2)√3

y=∑D sin(θ)
=25*sin(90°)+29sin(90-300°)
=25+29sin(-210°)
=25+29sin(30°)
=25+14.5
=39.5

Distance
=sqrt(x^2+y^2)
=...