Asked by Aron
Express each of the given question in logarithmic form.
i) e^2x = 15
ii) e^x-4 = 1/2
iii) a^x+1 = 5
Solutions
But am not sure if this is the way it should be done.
i) e^2x = 15
In (15) = 2x
ii) e^x-4 = 1/2
In (1/2) = x-4
iii) a^x+1 = 5
Log 5 with base "a" = x+1
i) e^2x = 15
ii) e^x-4 = 1/2
iii) a^x+1 = 5
Solutions
But am not sure if this is the way it should be done.
i) e^2x = 15
In (15) = 2x
ii) e^x-4 = 1/2
In (1/2) = x-4
iii) a^x+1 = 5
Log 5 with base "a" = x+1
Answers
Answered by
Damon
ln e^(2x)
= 2x = ln (15)
next two lack parentheses so I do not know if you mean
e^(x-4) or e^x - 4
If you just left the parens out, the bunch are right
= 2x = ln (15)
next two lack parentheses so I do not know if you mean
e^(x-4) or e^x - 4
If you just left the parens out, the bunch are right
Answered by
Aron
Ok and thanks alot. But those two are without parentheses.
Answered by
Damon
oh, well if e^x - 4 = 1/2
then e^x = 4.5
x = ln 4.5
but I wonder if that is what you mean
your book does not need parentheses as it does not need ^ sign for expoinents.
However on computer keyboard you must be more careful.
then e^x = 4.5
x = ln 4.5
but I wonder if that is what you mean
your book does not need parentheses as it does not need ^ sign for expoinents.
However on computer keyboard you must be more careful.
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