Asked by Anonymous
A uniform meter sick of mass 200 g is held horizontally by two vertical strings, one at the zero cm mark and the other at the 89 cm mark. Find the tension in the string at the 89 cm mark.
Answers
Answered by
Damon
T * .89 = .2 * g * .5
T = .1 (9.81) /.89
T = 1.1 Newtons
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