Asked by unknown
Q:the lion chasing the monkey at speed of 5m/s and speed of monkey is 3 m/s the distance b/w them is 25m after how much distance it catches the monkey?
Answers
Answered by
Henry
Dm = Vm*T.
Dl = Dm + 25.
Vl*T = Vm*T + 25.
5*T = 3*T + 25.
5T-3T = 25.
2T = 25.
T = 12.5 s. To catch up.
D = Vl*T = 5m/s * 12.5s. = 62.5 m. To
catch up.
Dl = Dm + 25.
Vl*T = Vm*T + 25.
5*T = 3*T + 25.
5T-3T = 25.
2T = 25.
T = 12.5 s. To catch up.
D = Vl*T = 5m/s * 12.5s. = 62.5 m. To
catch up.
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