Asked by ed
                a dog starts chasing a cat when they are 12 meters.  for every 7 meters that the dog runs, the cat runs 4 meters.  how far does the dog have to run to catch up with the cat?
            
            
        Answers
                    Answered by
            Reiny
            
    Let the distance run by the dog be 7x m
let the distance run by the cat be 4x m
so 7x = 4x + 12
3x = 12
x = 4
So the dog has to run 7(4) or 28 m to catch the cat.
check:
In the same time that the dog ran 28 m , the cat ran
16 m
but the cat had a 12 m head-start , giving us also 16+12 or 28 m
 
    
let the distance run by the cat be 4x m
so 7x = 4x + 12
3x = 12
x = 4
So the dog has to run 7(4) or 28 m to catch the cat.
check:
In the same time that the dog ran 28 m , the cat ran
16 m
but the cat had a 12 m head-start , giving us also 16+12 or 28 m
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