Asked by Hazel
what is the interval notation for solution set of the inequality x^2+16x is less than or equal to 0
Answers
Answered by
Steve
x^2+16x < 0
x(x+16) < 0
You know the graph crosses the x-axis at x=0,-16. So,
x(x+16) < 0 if -16<x<0
x(x+16) < 0
You know the graph crosses the x-axis at x=0,-16. So,
x(x+16) < 0 if -16<x<0
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