Ask a New Question

Question

What is the empirical formula for a molecule containing 52.20 grams manganese (Mn0 and 3.80 grams of Carbon (c)?
10 years ago

Answers

DrBob222
mols Mn = grams/atomic mass
mols C = grams/atomic mass

Now find the ratio to each other with the smallest being 1.00. The easy way to do that is to divide the smaller number by itself (which makes it 1.00), the divide the other number by the same small number. Round to whole numbers.
Post your work if you get stuck.
10 years ago
Aaliyah
Mn3C
9 years ago

Related Questions

What is the empirical formula of the oxide in Magnesium Oxide? The number of moles of Mg = 8.026 x 1... What is the empirical formula of caffeine (C8 H10 N4 O2)? How do I get it? Thanks What is the empirical formula of a compund composed of 3.25% hydrogen(H), 19.36% carbon(C) and 77.39... Given the Empirical formula: C6H7N, and a molecular mass of 372.52 g/mol, How do I find the MOLECULA... To fnd the empirical formula i have to convert the percent in g first, or a take the date in percent... What is the empirical formula of a molecule containing 65.5% carbon, 5.5% hydrogen, and 29.0% oxygen... empirical formula for K 60.0% C 18.5% N 21.5% and P 7.5% I 92.5% The empirical formula for the Brilliant Blue dye is: C37H34N2O9S3Na2 and the formula weight are 792.... What is the empirical formula of C6H6 A.CH B.C3H3 C.C6H6 D.3CH What is the empirical formula
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use