Asked by Sarah
25cm^3 H2SO4 is neutralized by 40 cm^3 of 0.03 mol/dm^3 KOH. What is the molar concentration of H2SO4?
Answers
Answered by
DrBob222
H2SO4 + 2KOH ==> K2SO4 + 2H2O
mols KOH = M x L = ?
Using the coefficients in the balanced equation, convert mols KOH to mols H2SO4.
Then M H2SO4 = mols H2SO4/L H2SO4.
mols KOH = M x L = ?
Using the coefficients in the balanced equation, convert mols KOH to mols H2SO4.
Then M H2SO4 = mols H2SO4/L H2SO4.
Answered by
Steve
40cm^3 * (1dm/10cm)^3 * .03mol/dm^3 = 0.0012 mol KOH
Each mole of H2SO4 needs 2 moles of KOH to be neutralized.
That means you had .0006 mol H2SO4
.0006mol/25cm^3 * 1000cm^3/L = 0.24mol/L = 0.24M H2SO4
Each mole of H2SO4 needs 2 moles of KOH to be neutralized.
That means you had .0006 mol H2SO4
.0006mol/25cm^3 * 1000cm^3/L = 0.24mol/L = 0.24M H2SO4
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