Asked by Dee Dee
                A pair of glasses are dropped from the top of a 32.0 m high stadium. A pen is dropped from the same position 2.00 s later. How long does it take for the glasses to hit the ground? How high above the ground is the pen when the glasses hit the ground? (Disregard air resistance)
            
            
        Answers
                    Answered by
            GK
            
    Find the time of fall by using:
y = (1/2)gt^2
(y is given and g = 9.8m/s^2, Solve for t)
When the glasses hit the ground, the pen has been falling for (t-2.00s). The height above the ground of the glasses is:
32.0m - (1/2)g(t-2)^2
    
y = (1/2)gt^2
(y is given and g = 9.8m/s^2, Solve for t)
When the glasses hit the ground, the pen has been falling for (t-2.00s). The height above the ground of the glasses is:
32.0m - (1/2)g(t-2)^2
                    Answered by
            GK
            
    Correction to the previous answer:
"The height above the ground of the <b>glasses</b> is:
32.0m - (1/2)g(t-2)^2" should read:
The height above the ground of the <b>pen</b> is:
32.0m - (1/2)g(t-2)^2
    
"The height above the ground of the <b>glasses</b> is:
32.0m - (1/2)g(t-2)^2" should read:
The height above the ground of the <b>pen</b> is:
32.0m - (1/2)g(t-2)^2
                    Answered by
            Gigjv
            
    2 m
    
                    Answered by
            merges
            
    25.6
    
                    Answered by
            Steve
            
    1.5 m
    
                    Answered by
            ryan
            
    30.51m
    
                    Answered by
            LYAN
            
    30.5
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.