Sarah has a collection of nickels, dimes, and quarters worth $9.25. She has 10 more dimes than nickels and twice as many quarters as dimes. How many coins of each kind does she have?

User Icon for Reiny Reiny answered
9 years ago

nickels --- x

dimes ---- x+10
quarters --- 2(x+10) = 2x + 20

now for the value of your coints

5x + 10(x+10) + 25(2x + 20) = 925

solve for x , easy to solve

User Icon for Clown Bot Clown Bot answered
1 year ago

Well, let's play with some numbers and solve this puzzle!

Let's start by assigning variables to the number of nickels, dimes, and quarters Sarah has.

Let N be the number of nickels,
Let D be the number of dimes,
And let Q be the number of quarters.

According to the information given, we know three things:

1. The total value of the coins is $9.25.
2. Sarah has 10 more dimes than nickels.
3. Sarah has twice as many quarters as dimes.

First, let's convert everything to cents to make the math a bit easier.

The value of N nickels is 5N cents.
The value of D dimes is 10D cents.
The value of Q quarters is 25Q cents.

So from the first piece of information, we know that 5N + 10D + 25Q = 925 cents.

Now, let's work on the second and third pieces of information.

Sarah has 10 more dimes than nickels, so D = N + 10.

Sarah has twice as many quarters as dimes, so Q = 2D.

Now we can substitute these expressions into the first equation to solve for N, D, and Q.

5N + 10D + 25Q = 925.

Substituting D = N + 10 and Q = 2D:

5N + 10(N + 10) + 25(2(N + 10)) = 925.

Simplifying:

5N + 10N + 100 + 50N + 500 = 925.

Combining like terms:

65N + 600 = 925.

Subtracting 600 from both sides:

65N = 325.

Dividing both sides by 65:

N = 5.

Now we know there are 5 nickels.

Using D = N + 10, we find D = 5 + 10 = 15.

Using Q = 2D, we find Q = 2 * 15 = 30.

So Sarah has 5 nickels, 15 dimes, and 30 quarters.

Now, it's time to help Sarah become a successful coin collector!

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

Let's solve this problem step by step.

Step 1: Assign variables.
Let's assume the number of nickels as "n", the number of dimes as "d", and the number of quarters as "q".

Step 2: Translate the given information into equations.
According to the problem, the value of all the coins is $9.25.
The value of a nickel is $0.05, the value of a dime is $0.10, and the value of a quarter is $0.25.

The equation for the total value of all the coins can be written as:
0.05n + 0.10d + 0.25q = 9.25 -- Equation 1

According to the problem, Sarah has 10 more dimes than nickels.
So, the equation for the number of dimes can be written as:
d = n + 10 -- Equation 2

According to the problem, Sarah has twice as many quarters as dimes.
So, the equation for the number of quarters can be written as:
q = 2d -- Equation 3

Step 3: Solve the system of equations.
To solve this system of equations, we will use the substitution method.

Substitute Equation 2 and Equation 3 into Equation 1:

0.05n + 0.10(n+10) + 0.25(2d) = 9.25
0.05n + 0.10n + 1.00 + 0.50d = 9.25
0.15n + 0.50d = 8.25 -- Equation 4

Now, substitute Equation 2 into Equation 4:

0.15n + 0.50(n+10) = 8.25
0.15n + 0.50n + 5.00 = 8.25
0.65n = 3.25
n = 5

Substitute the value of n into Equation 2:

d = n + 10
d = 5 + 10
d = 15

Substitute the value of d into Equation 3:

q = 2d
q = 2 * 15
q = 30

Step 4: Check the solution.
Let's check if our solution is correct by using the values of n = 5, d = 15, and q = 30 in Equation 1:

0.05n + 0.10d + 0.25q = 9.25
0.05(5) + 0.10(15) + 0.25(30) = 9.25
0.25 + 1.50 + 7.50 = 9.25
9.25 = 9.25

Since both sides of the equation are equal, our solution is correct.

Step 5: Answer the question.
Sarah has 5 nickels, 15 dimes, and 30 quarters.

User Icon for Explain Bot Explain Bot answered
1 year ago

To solve this problem, we can use a system of equations.

Let's start by assigning variables:
Let the number of nickels be N
Let the number of dimes be D
Let the number of quarters be Q

We can now translate the given information into equations.

1) The total value of the coins is $9.25:
The value of N nickels is 5N cents.
The value of D dimes is 10D cents.
The value of Q quarters is 25Q cents.
The sum of the values is 5N + 10D + 25Q.

Therefore, the equation is:
5N + 10D + 25Q = 925 (because $9.25 is equal to 925 cents)

2) Sarah has 10 more dimes than nickels:
The number of dimes is 10 more than the number of nickels.
Therefore, the equation is:
D = N + 10

3) Sarah has twice as many quarters as dimes:
The number of quarters is twice the number of dimes.
Therefore, the equation is:
Q = 2D

Now we have a system of three equations:

1) 5N + 10D + 25Q = 925
2) D = N + 10
3) Q = 2D

We can solve this system of equations using substitution or elimination.

Let's use the substitution method to solve this system:

Substitute D in terms of N from equation (2) into equations (1) and (3):

1) 5N + 10(N + 10) + 25Q = 925
2) Q = 2(N + 10)

Simplify equation (1):

5N + 10N + 100 + 25Q = 925
15N + 25Q = 825
3N + 5Q = 165

Multiply equation (2) by 5:

5Q = 10N + 50

Substitute the value of Q from equation (2) into equation (1):

3N + 5(10N + 50) = 165
3N + 50N + 250 = 165
53N = 165 - 250
53N = -85
N = -85/53 (rounded to the nearest whole number)

Since the number of coins cannot be negative, we know that N must be equal to 0.

Therefore, the number of nickels (N) is 0.

Substitute the value of N back into equation (2):

D = N + 10
D = 0 + 10
D = 10

Substitute the value of D back into equation (3):

Q = 2D
Q = 2(10)
Q = 20

So, Sarah has 0 nickels, 10 dimes, and 20 quarters.