Tim has more pennies than nickels, more nickels than dimes, more dimes than quarters, and more quarters than half-dollars. Tim has at least 3 quarters and at least one of each other kind of coin listed. What is the smallest number of cents Tim could have?

146+140+115+75+50 = 196cents

smallest number of quarters = 3

smallest number of dimes = 4
smallest number of nickels = 5
smallest number of pennies = 6
smallest number of half-dollars = 2

find the value of the above

PS, your initial answer makes no sense,
let me know what you get.

why 2 halves?

To determine the smallest possible number of cents Tim could have, let's start with the given information and work our way up.

We know that Tim has at least 3 quarters, so we can start with 3 quarters, which is equivalent to 75 cents.

Now, we need to consider the rest of the coins in the increasing order of their values.

Since Tim has more quarters than half-dollars, we can assume he has at least 1 half-dollar. A half-dollar is 50 cents.

Next, we know that Tim has more dimes than quarters, so we can assume he has at least 3+1 = 4 dimes. Each dime is worth 10 cents, so 4 dimes amount to 40 cents.

Moving on, Tim has more nickels than dimes, so we can assume he has at least 4+1 = 5 nickels. Each nickel is worth 5 cents, so 5 nickels amount to 25 cents.

Finally, Tim has more pennies than nickels, so we can assume he has at least 5+1 = 6 pennies. Each penny is worth 1 cent, so 6 pennies amount to 6 cents.

Now, let's add up the values of each coin: 75 cents (quarters) + 50 cents (half-dollar) + 40 cents (dimes) + 25 cents (nickels) + 6 cents (pennies) = 196 cents.

Therefore, the smallest number of cents Tim could have is 196 cents.