Sorry if I confused you. I miss-wrote my question.

Question

My question was: How can I determine the concentration of HCl remaining in the flask.

I calculated the # of moles of HCl neutralized by the tablet which was around 0.014 M.
I don't understand the steps needed to calculate the concentration of HCl remaining in the flask.
Given:
Con. of HCl: 0.14M
Volume added:100mL
Con. of NaOH:0.145M
Weight of Tablet: 1.3g

Answer 1

The mols HCl remaining in the flask after the tablet has been neutralized is just M NaOH x L NaOH = mols NaOH = mols HCl because that part of the reaction is
HCl + NaOH ==> NaCl + H2O