Asked by Anonymous

How many GRAMS of boron are present in 3.54 moles of boron trifluoride
Answered by DrBob222
How many mols of BF3 do you have? That's 3.54. How many mols B are in that. Since there is 1 mol B atoms in 1 mol BF3 molecules, there must be 3.54 x 1 = 3.54 mols B atoms.
Now convert mols B to grams with g B = mols B x atomic mass B.
Answered by Liz
38.26
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