Asked by Anonymous
Adam has 4 dimes, 4 quarters and 4 nickels in his pocket. He pulls out 2 coins making sure to put the first one back in his pocket before picking the second. What are the odds that he pulls out 2 nickels?
A. 1/3
B. 1/9
C. 1/16
D. 1/81
A. 1/3
B. 1/9
C. 1/16
D. 1/81
Answers
Answered by
Reiny
prob of 2 nickels = (4/12)(4/12)
= 1/9
so prob of not picking 2 nickels = 8/9
odds in favour of 2 nickels = (1/9) / (8/9)
= 1 : 8
none of the choices are correct for the ODDS
if you wanted the probability of getting 2 nickels it would be 1/9
the odds of an event is NOT the same as the probability of the event.
= 1/9
so prob of not picking 2 nickels = 8/9
odds in favour of 2 nickels = (1/9) / (8/9)
= 1 : 8
none of the choices are correct for the ODDS
if you wanted the probability of getting 2 nickels it would be 1/9
the odds of an event is NOT the same as the probability of the event.
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