ok, at that point you know how many moles of CaCO3 you have. Now look at the formula: for each mole of CaCO3, there is one mole of C.
Moles of C=250.0/100.1 to four decimal places (if your mole mass is correct)
How many moles of carbon are found in 250.0 g of CaCO3?
I started off with finding the molar mass of CaCO3, which is 100.09g. From there I divided 250g by 100.09g, but I have no idea what to do from there.
5 answers
If there is one mole of Carbon for every CaCO3, all I had to do was divide it and that would be my answer (2.498)? What if it was 2 moles of carbon instead of one, what would I have to do then?
What you have done now is
mols CaCO3 = g/molar mass = 250/100.09 = 2.498 mols.
Then convert from mols CaCO3 to mols C.
2.498 x (1 mol C/1 mol CaCO3) = 2.498 x 1/1 = 2.498 mols C.
Suppose the formula for CaCO3 was CaC2O3 (strictly a fictitious compound).
Then mols CaC2O3 in 250 g is 250/112.1 = 2.230. Now convert to mols C
2.230 mols CaC2O3 x (2 mols C/1 mol CaC2O3) = 2.230 x 2/1 = ?
mols CaCO3 = g/molar mass = 250/100.09 = 2.498 mols.
Then convert from mols CaCO3 to mols C.
2.498 x (1 mol C/1 mol CaCO3) = 2.498 x 1/1 = 2.498 mols C.
Suppose the formula for CaCO3 was CaC2O3 (strictly a fictitious compound).
Then mols CaC2O3 in 250 g is 250/112.1 = 2.230. Now convert to mols C
2.230 mols CaC2O3 x (2 mols C/1 mol CaC2O3) = 2.230 x 2/1 = ?
Just to recap:
I divide the grams of the compound by its molar mass. From there, I do the mol conversion from CaCO3 to C and that will by my answer.
I divide the grams of the compound by its molar mass. From there, I do the mol conversion from CaCO3 to C and that will by my answer.
yes. It's two steps.
1. Convert grams you have to mols.
2. Convert mols of what you have to mols of what you want.
1. Convert grams you have to mols.
2. Convert mols of what you have to mols of what you want.
3 answers