Question
The rider of a ferris wheel moves at a rate of 0.18 m/s2. If the rider is 5.0 m from the center of the ferris wheel, What is his/her Velocity?
Can't figure out if the RADIUS and RATE are the same and Which one is the radius/rate?
Can't figure out if the RADIUS and RATE are the same and Which one is the radius/rate?
Answers
Damon
radius = 5 meters
.18 m/s^2 is probably the centripetal acceleration. I can not imagine why it is called "rate".
acceleration = v^2/R
v^2 = .18 * 5 = .9
v = .95 m/s
.18 m/s^2 is probably the centripetal acceleration. I can not imagine why it is called "rate".
acceleration = v^2/R
v^2 = .18 * 5 = .9
v = .95 m/s
LALA
Omygossh thanks damon!!! :)
Alfonz
I was trying to solve this problem just now for our HW. I got so confused. But thanks to Damon I now understand it very clearly
Cali
What is the velocity of a ferris wheel rider sitting at a distance of 5.0 m from the center of rotation while moving at a rate of 18 m/s²? With solution