Asked by LALA
The rider of a ferris wheel moves at a rate of 0.18 m/s2. If the rider is 5.0 m from the center of the ferris wheel, What is his/her Velocity?
Can't figure out if the RADIUS and RATE are the same and Which one is the radius/rate?
Can't figure out if the RADIUS and RATE are the same and Which one is the radius/rate?
Answers
Answered by
Damon
radius = 5 meters
.18 m/s^2 is probably the centripetal acceleration. I can not imagine why it is called "rate".
acceleration = v^2/R
v^2 = .18 * 5 = .9
v = .95 m/s
.18 m/s^2 is probably the centripetal acceleration. I can not imagine why it is called "rate".
acceleration = v^2/R
v^2 = .18 * 5 = .9
v = .95 m/s
Answered by
LALA
Omygossh thanks damon!!! :)
Answered by
Alfonz
I was trying to solve this problem just now for our HW. I got so confused. But thanks to Damon I now understand it very clearly
Answered by
Cali
What is the velocity of a ferris wheel rider sitting at a distance of 5.0 m from the center of rotation while moving at a rate of 18 m/s²? With solution
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.