Asked by Ocean

How many grams of Fe(NO3)2 are present in 555mL of a 0.650 M solution of Fe(NO3)2??
I have no clue what to do??
Answered by Damon
Fe = 56
2N =2*14 = 28
6O = 6*16 = 96
so the stuff is 180 grams/mol

.555 * .650 = .361 mols present

.361 * 180 = 65 grams
Answered by Ocean
Oh my gosh you're awesome!!!!!! Thanks
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