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A BOATMAN ROWS TO A PLACE 48KM DISTANT AND BACK IN 14 HOURS; HE FINDS HE CAN ROW 4KM WITH THE STREAM IN THE SAME TIME AS 3KM AG...Question
A BOATMAN ROWS TO A PLACE 48KM DISTANT AND BACK IN 14 HOURS; HE FINDS HE CAN ROW 4KM WITH THE STREAM IN THE SAME TIME AS 3KM AGAINST THE STREAM. FIND THE RATE OF THE STREAM?
Answers
Steve
If his rowing speed is r, and the current speed is c, then
(r+c)/4 = (r-c)/3
48/(r+c) + 48/(r-c) = 14
c = 1
(r+c)/4 = (r-c)/3
48/(r+c) + 48/(r-c) = 14
c = 1
Cedrick Bryll Castulo Sison
Suppose he move 4 km downstream in x hours. Then,
Speed downstream = 4 km/hr.
x
Speed upstream = 3 km/hr.
x
48 + 48 = 14 or x = 1 .
(4/x) (3/x) 2
So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.
Rate of the stream = 1 (8 - 6) km/hr = 1 km/hr.
2
Speed downstream = 4 km/hr.
x
Speed upstream = 3 km/hr.
x
48 + 48 = 14 or x = 1 .
(4/x) (3/x) 2
So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.
Rate of the stream = 1 (8 - 6) km/hr = 1 km/hr.
2