Asked by nothing

a bullet moving with a velocity of 10m/s is stopped after penetrating the wooden plank of 4 cm of thickness. calculate acceleration of the bullet
Answered by Henry
V^2 = Vo^2 + 2a*d = 0
10^2 + 2a*0.04 = 0
2a*0.04 = -100
a = -1250 m/s.

Note: The negative sign means that the
acceleration opposes the motion.

Answered by harsh
initial velocity=10m/s
final velocity=0m/s
distance traveled=4cm=0.04m
using equation of motion(v^2-u^2=2as)=
0-100=2as
=-100=2*a*0.04
-100=0.08a
a=-100/8/100=-10000/8
=-1250
Answered by arushi
initial velocity=10m/s
final velocity=0m/s
distance traveled=4cm=0.04m
using equation of motion(v^2-u^2=2as)=
0-100=2as
=-100=2*a*0.04
-100=0.08a
a=-100/8/100=-10000/8
=-1250
Answered by better than you
initial velocity=10m/s
final velocity=0m/s
distance traveled=4cm=0.04m
using equation of motion(v^2-u^2=2as)=
0-100=2as
=-100=2*a*0.04
-100=0.08a
a=-100/8/100=-10000/8
=-125
Answered by Rita Das
initial velocity=10m/s
final velocity=0m/s
distance traveled=4cm=0.04m
using equation of motion(v^2-u^2=2as)=
0-100=2as
=-100=2*a*0.04
-100=0.08a
a=-100/8/100=-10000/8
=-1250
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