Asked by Rishav
if cosA= -1/2 and π<A<3π/2 then find the value of 4tan^2A-3cosec^2A ?
Answers
Answered by
Steve
in QIII, tan is positive and csc is negative. (doesn't really matter, since they're both squared in the expression.) So,
sinA = -√3/2
tanA = √3
csc^2 = 1+tan^2, so
4tan^2-3csc^2 = tan^2A-3 = 0
sinA = -√3/2
tanA = √3
csc^2 = 1+tan^2, so
4tan^2-3csc^2 = tan^2A-3 = 0
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