Asked by Anonymous
how do you do this question
(3^-3 + 3^-4)/3^-5
(3^-3 + 3^-4)/3^-5
Answers
Answered by
Steve
3^-3 + 3^-4 = 3*3^-4 + 3^-4
= (3+1)*3^-4 = 4*3^-4
Recall that a negative exponent switches between top and bottom in fractions. So,
4*3^-4/3^-5 = 4/3^4 * 3^5 = 4*3 = 12
= (3+1)*3^-4 = 4*3^-4
Recall that a negative exponent switches between top and bottom in fractions. So,
4*3^-4/3^-5 = 4/3^4 * 3^5 = 4*3 = 12
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