Asked by karen
f(x)=2secx-tanx, -π/2<x<π/2
find the points at which the tangent is horizontal
find the points at which the tangent is horizontal
Answers
Answered by
bobpursley
f'=0=2secxtanx-sec^2x
secx(2tanx-sex)=0
secx=0 or tanx=1/2 secx which leads to
sinx=.5
now, because secx cannot be zero, then
sinx=.5
or x=30 deg or PI/6
secx(2tanx-sex)=0
secx=0 or tanx=1/2 secx which leads to
sinx=.5
now, because secx cannot be zero, then
sinx=.5
or x=30 deg or PI/6
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