Asked by Yumin
1. Evaluate ∫(0-4) x/√x^2+9 dx
2. Given F(x)= ∫(0-x) t√t^2+4 dt, find F'(x)
2. Given F(x)= ∫(0-x) t√t^2+4 dt, find F'(x)
Answers
Answered by
Steve
#1
Let
u = x^2+9
du = 2x dx
and you have
∫ 1/2 √u du
That's easy, right?
From the 2nd Fundamental Theorem of Calculus,
F'(x) = f(x) = x√(x^2+4)
Let
u = x^2+9
du = 2x dx
and you have
∫ 1/2 √u du
That's easy, right?
From the 2nd Fundamental Theorem of Calculus,
F'(x) = f(x) = x√(x^2+4)
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