Asked by Anonymous

a news carrier has $7.00 in change he has 8 more quarters than dimes and five times as many nickels than quarters.how many coins of each type does he have ?
Answered by Steve
q = d+8
n = 5q
5n+10d+25q = 700

Now just plug and play!
Answered by Reiny
let's start with dimes ---- x
then quarters ---- x+8
nickels ------- 5(x+8)

now to the VALUE of these

10x + 25(x+8) + 5(5)(x+8) = 700
10x + 25x + 200 + 25x + 200 = 700
60x = 300
x = 5
so

5 dimes
13 quarters
65 nickels

check:
5(10) + 13(25) + 65(5) = 700
my answer is correct
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