Asked by Erica
A newspaper carrier has $4.00 in change. He has two more quarters than dimes but five times as many nickels as quarters. How many of coins of each type does he have.
This is what I got so far and then I get lost.
dimes = x
quarters = x+2
nickels = 5(x+2)
10x+25(x+2)+5*4(x+2)= 400
55x + 90 -90 = 400 - 90
55x= 310
55x/55 = 310/55
x=
I am doing some wrong somewhere and I do not know where.
This is what I got so far and then I get lost.
dimes = x
quarters = x+2
nickels = 5(x+2)
10x+25(x+2)+5*4(x+2)= 400
55x + 90 -90 = 400 - 90
55x= 310
55x/55 = 310/55
x=
I am doing some wrong somewhere and I do not know where.
Answers
Answered by
PsyDAG
10x+25(x+2)+5*<B>5</B>(x+2)= 400
10x + 25x +50 + 25x + 50 = 400
55x = 300
x = 300/55 = 5.45
I found one mistake in you equation above (bold), but that still does come out right. Do you have any typos?
10x + 25x +50 + 25x + 50 = 400
55x = 300
x = 300/55 = 5.45
I found one mistake in you equation above (bold), but that still does come out right. Do you have any typos?
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