Asked by Anne
Terms 1 through 5 of a sequence are shown below.
8/81 , 4/27 , 2/9 , 1/3 , 1/2
What is the 10th term in the sequence?
I have no clue. I tried having common denominator of 81, but that just confused me more. I would try to show more work, but I really don't know how to approach the problem?
8/81 , 4/27 , 2/9 , 1/3 , 1/2
What is the 10th term in the sequence?
I have no clue. I tried having common denominator of 81, but that just confused me more. I would try to show more work, but I really don't know how to approach the problem?
Answers
Answered by
Steve
Find the ratio of the 1st two terms:
(4/27) / (8/81) = 4/27 * 81/8 = 3/2
You can easily verify that each term is 3/2 the previous one. So,
So, a10 = 8/81 * (3/2)^9
= 2^3/3^4 * 3^9/2^9
= 3^5/2^6
= 243/64
(4/27) / (8/81) = 4/27 * 81/8 = 3/2
You can easily verify that each term is 3/2 the previous one. So,
So, a10 = 8/81 * (3/2)^9
= 2^3/3^4 * 3^9/2^9
= 3^5/2^6
= 243/64
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